OXFORD

UNIVERSITY PRESS

New Century Senior Physics

 - Concepts in Context

2nd Edition - 2004

- by Richard Walding, Greg Rapkins and Glenn Rossiter

 



ERRATA

We've found a couple few more of errors in the text.

Chapter 1, p11: Subheading "Further Examples" (a) should be "radius of the Sun". Thank you to Joshua Noronha, St. Laurence’s College, Brisbane.

Chapter 2, p33: 4th line from bottom. Answer to final part of example should be negative (-3.3 m s-1). Credit to Michael Schobbe, Year 11, Caboolture SHS.

Chapter 2, p 50, Q40 about Brett Lee. Answer is 20 ÷ (157.4 ×1000/(60×60) = 0.46 s not 0.55 s as stated on p761. Credit to Alyssa Young, Year 11, Caboolture SHS.

Chapter 3, p57: Lines 4 & 5 should read "...but is heading north-west." Spotted by Michael Leask.

Chapter 3, p 60. The answer to Q4 should say that "height" is a vector (not a scalar) at it indicates direction as well as magnitude. Thank you to Michael Leask, Caboolture SHS

Chapter 4, Q20: Answer should be (a) (i) 3.04 m s-2; (ii) T = 104 N

Chapter 4, Q49: The angle was wrong. the answer is: Using trigonometry: the wind force FH = FW tan 37° = 2.26 x 10-3 N. Thank you to Bryan Corcoran for his eagle eye.

Chapter 4, Q59: Answer should be 15.3 m s-1 (see worked solutions web page).

Chapter 4, Q61: Answer is 953 N. Thank you to Brianna Towers for finding this.

Chapter 5, p112: Novel Challenge. The Acapulco cliff diver landed 5 m from the base of the cliff, not 5 mm. Thank you to Joshua Noronha, St. Laurence’s College, Brisbane.

Chapter 5, p 114. Activity 5.3.  (a) should read Horizontal range sh= u cos q × t = R; velocity at maximum vertical height vv = u sin q + at/2 = 0. Thanks to Rod Duncan for pointing that out.

Chapter 5, p129, Q26(d). The answer on page 763 for the horizontal range should be in "m" not "m/s". Thank you to Tristan Ockwell, St. Laurence’s College, Brisbane.

Chapter 6, p140. In Figure 6.2, the last number on the x-axis should be 1015 not 10-15. Thank you to Michael Leask, Science Teacher at Caboolture State High School.

Chapter 6, p 137. Table 6.1 has wrong data in the Ca-H and Ha columns. The correct values are shown below. My thanks to Physics teaches Victor Braun (for pointing out the error) and Mark Shields (for giving me the correct values). Scratchies on their way chaps.
 
  Ca-H Ha
  396.9 656.3

Virgo

398.4

658.8

Perseus

404.1

668.2

Hercules

410.7

679.1

Pegasus II

413.8

684.3

Ursa Major 1

416.7

689.1

Gemini

427.9

707.5

Ursa Major 2

450.3

744.7

Hydra

476.9

788.7

3C295

579.5

958.2

Chapter 6, p143. Physics fact: the spin of 1998KY26 takes 10.7 minutes not seconds. And the next line about the day being 0.09 seconds doesn't even make sense. Delete it! Thank you again to Michael Leask at Caboolture State High School.

Chapter 7, Q5, p172. The answer should be 9458 N not 9690 N as we have in the back of the book. We (I) used the density of freshwater (1000 kg m-3 instead of saltwater (1030 kg m-3). Thank you yet again to Michael Leask at Caboolture State High School. We owe you a moche latte.

Chapter 8, Q16. Correct answer is 16.3 m s-1. I'm not sure how we got that one wrong. A big thank you and two cans of Red Bull to the men with the keen eyes from St Laurences' College, Brisbane: Joshua Noronha and Duy Nguyen. Thanks again chaps!

Chapter 8, Q 14 (b), p197. The answer is 2.71 m/s not -1.86 m/s. The working is as follows:

As the jet is backwards (v=-35m/s) then (with bullet a, melon b and jet c)

ma.ua  = (ma + mb - mc).v + mc.vc

0.01x545      = (0.01+3-0.3)v+0.3x-35

5.45 + 10.5  = 2.71 m/s    (not -1.86!?). A big thank you to the Kennedy Assassination buff and Physics teacher Chris Smith (and his Yr 11 Physics class) at Sunshine Coast Grammar School.

Chapter 8, p206. In the solution to the example, the linear momentum should be 2.9 x 10-3 not 2.9 x 10-3. Also, for the rotational momentum the radius part should read (2.78 x 10-3)2 not (2.78 x 10-3)2. That's not my fault - that's the typesetter stuffing things up afterwards. But, I guess I should have checked. Thanks boys: that's Joshua Noronha & Ryan Schumacher from St Laurences' College, Brisbane again. This is getting embarrassing.

Chapter 10, Q40. Correct answer is 0.2 cm. See worked solutions. Credit to Anthony Reid, North Lakes State College. We owe you a half-strength decaf mocha latte.

Chapter 11, page 264 Table 11.1. The units for alpha should be °C-1 not m °C-1 Thank you to Vic Braun for spotting that.

Chapter 11, page 267 Table 11.2. The units for beta should be °C-1 not m °C-1 Thank you again to Vic Braun for spotting that.

 Chapter 13, Q38. Correct answer is Open Pipe formula: L = nl/4, where n = 1, 2, 3, 4, 5 (see webpage for diagram). Big thank you to the eagle eyed Joshua Noronha (St Laurances).

Chapter 15, p326. Example, parts (c) and (d). The wavelength of 600nm found in part (b) has not been used in parts (C) and (D) - in fact 640nm has been used for some unknown reason (fat fingers?). The correct answer for (c) should be 2.25 x 10-2 m; and the correct answer for (d) should be x = 4.4 mm, thus thickness = 9.0 mm. As well, the formula in the box for (d) has some typos: the numerator on the LHS should read (1- ½) x 600 x 10-9. My thanks again to Joshua Noronha (St Laurances). Goodness knows what he'll find in Chapter 16. I can hardly wait.

Chapter 19, p 421. The text referring to Figure 19.8(c) under the subheading "Characteristics of the image" is wrong. Delete the words "between F and the lens" - this is clearly wrong. Thank you to Ron Grant for his eagle eye.

Chapter 19 Q15, p426. It should say that the image was found on a screen.  Thanks Ron.

Chapter 19 Q27, p428. The answer in the back is wrong but the worked solution on the web page is correct. Thanks Ron.

Chapter 27. Questions 18 to 28 have the answers in the back (page 768) as Q19-29. Thank you to Kevin Fullbrook - Gold Coast Institute of TAFE  for pointing that out.

Chapter 28, page  624 Predicting the type of decay. The two dot points are in conflict with the graph on page 625. The graph is correct. The dot points should read:

  • Beta decay will occur in those nuclides that are BELOW the line of stability.
  • Positron decay will occur in those nuclides that are ABOVE the line of stability. Thanks to Dylan Hudson, Year 12 Launceston College for pointing this out.

    Chapter 27 p 615: Figure 27.22 is said to be for question 29, but is for question 28. Likewise Figures 27.21 and 27.20 are said to be for questions 25 and 28 respectively, but in fact relate to questions 24 and 27. Thanks to David Wiseman - Year 12 student at Toowoomba State High School - for spotting that.

    Chapter 28, page  625: the reaction at the bottom of the page should have as the product C-13 not C-12. David Wiseman yet again.

    Chapter 28, page  625. Q9a has a wrong answer in the back of the book. It should read Na-22 as in the question. The rest is okay. Thanks to David Wiseman from Toowoomba SHS for spotting that too.

    Chapter 28 p 629, first line under the N-13 decay equation. Should read "nitrogen" not "sodium". I think I had a brain freeze. Mr Pedantic - David Wiseman - from Toowoomba SHS again.

    Chapter 28 p 645: This is not really an error but to keep Mr Pedantic (David Wiseman) happy I will acknowledge that the sentence could be written more clearly. He said that his friend Steven Connell is disturbed with the statement six lines from the bottom that says '    Radiation that deposits one joule of energy per kilogram of tissue is called the absorbed dose.'   David said "However, radiation that deposits one joule per kilogram would have an absorbed dose of one gray. I think the sentence should read something like 'The absorbed dose is the radiation absorbed in joules per kilogram of tissue'". Thanks again David, I will make the change in the next edition. You should get a job with Oxford University Press as a proofreader (it would get you off my back).
     
    Chapter 29, p661. Jayke Anderson from Caboolture State High School pointed out that the equation used for solution part (c), v=f    λ, is missing λ in the rearrangement. I would have sent a $2 Scratchie if it wasn't for the Global Financial Crisis.

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