OXFORD

UNIVERSITY PRESS

New Century Senior Physics

 - Concepts in Context



2nd Edition - 2004

- by Richard Walding, Greg Rapkins and Glenn Rossiter

 



ERRATA

We've found a couple few more of errors in the text.

Chapter 1, p11: Subheading "Further Examples" (a) should be "radius of the Sun". Thank you to Joshua Noronha, St. Laurence’s College, Brisbane.

Chapter 2, p33: 4th line from bottom. Answer to final part of example should be negative (-3.3 m s-1). Credit to Michael Schobbe, Year 11, Caboolture SHS.

Chapter 2, p 50, Q40 about Brett Lee. Answer is 20 ÷ (157.4 ×1000/(60×60) = 0.46 s not 0.55 s as stated on p761. Credit to Alyssa Young, Year 11, Caboolture SHS.

Chapter 3, p57: Lines 4 & 5 should read "...but is heading north-west." Spotted by Michael Leask.

Chapter 3, p 60. The answer to Q4 should say that "height" is a vector (not a scalar) at it indicates direction as well as magnitude. Thank you to Michael Leask, Caboolture SHS

Chapter 4, Q20: Answer should be (a) (i) 3.04 m s-2; (ii) T = 104 N

Chapter 4, Q59: Answer should be 15.3 m s-1 (see worked solutions web page).

Chapter 4, Q61: Answer is 953 N. Thank you to Brianna Towers for finding this.

Chapter 5, p112: Novel Challenge. The Acapulco cliff diver landed 5 m from the base of the cliff, not 5 mm. Thank you to Joshua Noronha, St. Laurence’s College, Brisbane.

Chapter 5, p 114. Activity 5.3.  (a) should read Horizontal range sh= u cos q × t = R; velocity at maximum vertical height vv = u sin q + at/2 = 0. Thanks to Rod Duncan for pointing that out.

Chapter 5, p129, Q26(d). The answer on page 763 for the horizontal range should be in "m" not "m/s". Thank you to
Tristan Ockwell, St. Laurence’s College, Brisbane.

Chapter 6, p140. In Figure 6.2, the last number on the x-axis should be 1015 not 10-15. Thank you to Michael Leask, Science Teacher at Caboolture State High School.

Chapter 6, p143. Physics fact: the spin of 1998KY26 takes 10.7 minutes not seconds. And the next line about the day being 0.09 seconds doesn't even make sense. Delete it! Thank you again to Michael Leask at Caboolture State High School.

Chapter 7, Q5, p172. The answer should be 9458 N not 9690 N as we have in the back of the book. We (I) used the density of freshwater (1000 kg m-3 instead of saltwater (1030 kg m-3). Thank you yet again to Michael Leask at Caboolture State High School. We owe you a moche latte.

Chapter 8, Q16. Correct answer is 16.3 m s-1. I'm not sure how we got that one wrong. A big thank you and two cans of Red Bull to the men with the keen eyes from St Laurences' College, Brisbane: Joshua Noronha and Duy Nguyen. Thanks again chaps!

Chapter 8, Q 14 (b), p197. The answer is 2.71 m/s not -1.86 m/s. The working is as follows:

As the jet is backwards (v=-35m/s) then (with bullet a, melon b and jet c)

ma.ua  = (ma + mb - mc).v + mc.vc

0.01x545      = (0.01+3-0.3)v+0.3x-35

5.45 + 10.5  = 2.71 m/s    (not -1.86!?). A big thank you to the Kennedy Assassination buff and Physics teacher Chris Smith (and his Yr 11 Physics class) at Sunshine Coast Grammar School.

Chapter 8, p206. In the solution to the example, the linear momentum should be 2.9 x 10-3 not 2.9 x 10-3. Also, for the rotational momentum the radius part should read (2.78 x 10-3)2 not (2.78 x 10-3)2. That's not my fault - that's the typesetter stuffing things up afterwards. But, I guess I should have checked. Thanks boys: that's Joshua Noronha &
Ryan Schumacher from St Laurences' College, Brisbane again. This is getting embarrassing.

Chapter 10, Q40. Correct answer is 0.2 cm. See worked solutions. Credit to Anthony Reid, North Lakes State College. We owe you a half-strength decaf mocha latte.


Chapter 13, Q38. Correct answer is Open Pipe formula: L = nl/4, where n = 1, 2, 3, 4, 5 (see webpage for diagram). Big thank you to the eagle eyed Joshua Noronha (St Laurances).

Chapter 15, p326. Example, parts (c) and (d). The wavelength of 600nm found in part (b) has not been used in parts (C) and (D) - in fact 640nm has been used for some unknown reason (fat fingers?). The correct answer for (c) should be 2.25 x 10-2 m; and the correct answer for (d) should be x = 4.4 mm, thus thickness = 9.0 mm. As well, the formula in the box for (d) has some typos: the numerator on the LHS should read (1- ½) x 600 x 10-9. My thanks again to Joshua Noronha (St Laurances). Goodness knows what he'll find in Chapter 16. I can hardly wait.

Chapter 19, p 421. The text referring to Figure 19.8(c) under the subheading "Characteristics of the image" is wrong. Delete the words "between F and the lens" - this is clearly wrong. Thank you to Ron Grant for his eagle eye.

Chapter 19 Q15, p426. It should say that the image was found on a screen.  Thanks Ron.

Chapter 19 Q27, p428. The answer in the back is wrong but the worked solution on the web page is correct. Thanks Ron.

Chapter 27. Questions 18 to 28 have the answers in the back (page 768) as Q19-29. Thank you to Kevin Fullbrook - Gold Coast Institute of TAFE  for pointing that out.

Chapter 28, page  624 Predicting the type of decay. The two dot points are in conflict with the graph on page 625. The graph is correct. The dot points should read:

  • Beta decay will occur in those nuclides that are BELOW the line of stability.
  • Positron decay will occur in those nuclides that are ABOVE the line of stability. Thanks to Dylan Hudson, Year 12 Launceston College for pointing this out.

    Chapter 29, p661. Jayke Anderson from Caboolture State High School pointed out that the equation used for solution part (c), v=f
    λ, is missing λ in the rearrangement. I would have sent a $2 Scratchie if it wasn't for the Global Financial Crisis.

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